Explanation Let us assume that s be the length of the side of the square and h be the height of the square box. Then, V = s 2 h = 72 By rearranging: h = 72 s 2 Therefore, the cost of the box is C = 40 s 2 + 120 s h C = 40 s 2 + 8640 s 2 C <

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 4.6, Problem 43E

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To find out the dimension of the box which will minimize the cost of production.

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Chapter 4.6, Problem 42E

Chapter 4.6, Problem 44E

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Chapter 4 Solutions

Calculus - Standalone book

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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To find out the dimension of the box which will minimize the cost of production.

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To find out the dimension of the box which will minimize the cost of production.

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Chapter 4 Solutions