Explanation Given: y = θ − 2 sin θ , [ 0 , 2 π ] Critical points of θ − 2 sin ( θ ) , 0 ≤ θ ≤ 2 π : θ = 0 , θ = π 3 , θ = 5 π 3 , θ = 2 π Find where f ' ( x ) is equal to zero or undefined d d θ ( θ − 2 sin ( θ ) ) = d d θ ( θ ) − d d θ ( 2 sin ( θ ) ) = = d d θ ( θ ) − d d θ ( 2 sin ( θ ) ) d d θ ( θ ) = 1 d d θ ( θ ) Apply the common derivative d d θ ( θ ) = 1 ( a

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 4.2, Problem 47E

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y=θ−2sin θ, [0,2π]

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Chapter 4.2, Problem 46E

Chapter 4.2, Problem 48E

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Chapter 4 Solutions

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Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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y = θ − 2 sin θ , [ 0 , 2 π ]

Solution Summary: The author explains that it can be need to evaluate interval endpoint theta =0 critical point.

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y=θ−2sin θ, [0,2π]

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