Explanation Given: d d θ ( θ − 2 cos ( θ ) ) = d d θ ( θ ) − d d θ ( 2 cos ( θ ) ) d d θ ( θ ) Apply the common derivative : d d θ ( θ ) = 1 =1 d d θ ( 2 cos ( θ ) ) = 2 d d θ ( cos ( θ ) ) = 2 ( − sin ( θ ) ) = 1 + 2 sin ( θ ) 1 + 2 sin ( θ ) = 0 , 0 ≤ θ ≤ 2 π Subtract 1 from both sides 1 + 2 sin ( θ <

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 4.3, Problem 48E

To determine

Find the critical point and endpoint at the minimum and maximum value of the function of y=θ−2cos θ,[0,2π].

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Chapter 4.3, Problem 47E

Chapter 4.3, Problem 49E

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Find the critical point and endpoint at the minimum and maximum value of the function of y = θ − 2 cos θ , [ 0 , 2 π ] .

Solution Summary: The author explains how to determine the critical point and endpoint at the minimum and maximum value of the function of y=theta -2cos

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Find the critical point and endpoint at the minimum and maximum value of the function of y=θ−2cos θ,[0,2π].

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Chapter 4 Solutions