Explanation Given information: A function is given as, y = sec 2 x − 2 tan x on interval [ − π 6 , π 3 ] . Calculation: A function is given as, y = sec 2 x − 2 tan x on interval [ − π 6 , π 3 ] . Now let us first find the critical points. y = sec 2 x − 2 tan x ⇒ y ' = 2 sec 2 x tan x − 2 sec 2 x ⇒ y ' = 2 sec 2 x ( tan x − 1 ) At critical points, y ' = 0 ⇒ 2 sec 2 x ( tan x − 1 ) = 0 ⇒ sec x = 0 ⇒ This is not possible . and tan x − 1 = 0 ⇒ tan x = 1 ⇒ x = π 4 Now calculating function values at the critical points and extreme points of interval [ − π 6 , π 3 ]

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 4.2, Problem 50E

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Chapter 4.2, Problem 49E

Chapter 4.2, Problem 51E

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Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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