x² - y² (10 points) Let f(x,y): = (a) (6 points) For each vector u = (1, 2), calculate the directional derivative Duƒ(1,1). (b) (4 points) Determine all unit vectors u for which Duf(1, 1) = 0.
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- Find the maximum rate of change of f(x, y) Maximum rate of change: 2/5 In(x? + y?) at the point (-4, -3) and the direction in which it occurs. Direction (unit vector) in which it occurs: -8/25 -6/25 出)What is the velocity vector?Find the scalar equation for each line: (a) a line through the point (-6, 7) with direction vector (-5,) (b) the line (x, y) = (2,22) + (-3,17):
- Find the directional derivative of f (x, y, z) = 2z²x + y³ at the point (2, 1, 1) in the direction of the vector √5 (Use symbolic notation and fractions where needed.) directional derivative: + 2 √5Find the directional derivative of f (x, y, z) = 2z²x + y° at the point (2, 1, 2) in the direction of the vector 1 2 i+ (Use symbolic notation and fractions where needed.) directional derivative:calculate speed only, the rest are done.
- Find the directional derivative of the function at the given point in the direction of the vector v. g(p, q) = p4 − p2q3, (1, 1), v = i + 2jFind the velocity vector v(t), given the acceleration vector a(t) = (3e¹, 7, 10t +9) and the initial velocity v(0) = (8,-5,3). (Use symbolic notation and fractions where needed. Give your answer in the vector form.) v(t) = 2(e' - 2)i + (3t-2)j + (3r² +9r+2)k IncorrectGiven the function y = 5 - x². (a) Find the equation of the line normal to the curve at the point P: (1,4). (b) Write your answer in vector format using the 2D unit vectors î, J.