Explanation Write the expression for the energy balance equation. E in − E out = Δ E system (I) Here, the total energy entering the system is E in , the total energy leaving the system is E out , and the change in the total energy of the system is Δ E system . Simplify Equation (I) and write energy balance relation of spring-loaded piston-cylinder device. W b,in − Q out = Δ U Q out = W b,in − Δ U Q out = W b,in − m ( u 2 − u 1 ) (II) Here, the work to be done into the system is W b,in , the heat to be transfer by the system is Q out , the change in the internal energy of a spring-loaded piston-cylinder device is Δ U water , the mass of the spring-loaded piston-cylinder device is m , the initial specific internal energy of spring-loaded piston-cylinder device is u 1 , and the final specific internal energy of spring-loaded piston-cylinder device is u 2 . Simplify the Equation (II) in unit per mass. q out = w b,in − ( u 2 − u 1 ) (III) Write the expression for work done area under the state 1-2. W b,out = Area = P 1 + P 2 2 ( V 2 − V 1 ) (IV) Here, the initial pressure of the process state 1 is P 1 , the final pressure of the process state 2 is P 2 , the initial volume of spring-loaded piston-cylinder device is V 1 , and the final volume of spring-loaded piston-cylinder device is V 2 . Conclusion: From the Table A-4 “Saturated water-temperature” at 200 C and 50 C obtain the value of initial pressure, initial specific volume, initial specific internal energy, final pressure, final specific volume, and final specific internal energy. P 1 = 1555 kPa . v 1 = 0.1272 m 3 / kg . u 1 = 2594.2 kJ / kg . P 2 = 12.35 kPa . v 2 = 0.001012 m 3 / kg . u 2 = 209.33 kJ / kg . Substitute 1555 kPa for P 1 , 12

9th Edition

ISBN: 9781259822674

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

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Chapter 4.5, Problem 122RP

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The heat transfer for the process in kJ/kg.

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The heat transfer for the process in kJ / kg .

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