Oxidation number of the given compound and ion has to be assigned. Concept introduction: The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number. Rules in assigning the oxidation number: In free state, each atom has zero oxidation number. Charge of a monoatomic ion is same as its oxidation number. Sum of the oxidation number of neutral compound is zero. Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively. The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

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Answer 1

Question

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

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Answer 2

Question

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

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Answer 3

Question

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

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Answer 4

Question

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

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Answer 5

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

Answer 6

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

Answer 7

Chapter 4.4, Problem 1PE

(a)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free state, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

Answer 9

(b)

Interpretation Introduction

Interpretation:

Oxidation number of the given compound and ion has to be assigned.

Concept introduction:

The number of charges an atom would have in a molecule or ion if electrons were transferred completely is called oxidation number.

Rules in assigning the oxidation number:

In free State, each atom has zero oxidation number.

Charge of a monoatomic ion is same as its oxidation number.

Sum of the oxidation number of neutral compound is zero.

Group 1, group 2, group 3; has oxidation number +1, +2 and +3 respectively.

The sum of the oxidation number of atoms in polyatomic ion is equal to the charge of the ion.

Answer 10

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Answer 13

Ch. 4.1 - Prob. 1RC Ch. 4.2 - Practice Exercise Classify the following ionic...Ch. 4.2 - Practice Exercise Predict the precipitate produced...Ch. 4.2 - Prob. 1RC Ch. 4.3 - Practice Exercise Classify each of the following...Ch. 4.3 - Prob. 2PE Ch. 4.3 - Prob. 1RC Ch. 4.4 - Practice Exercise Assign oxidation numbers to all...Ch. 4.4 - Prob. 2PE Ch. 4.4 - Prob. 1RC

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