Chapter 4, Problem 4.91QP

Interpretation Introduction

Interpretation:

The volume of ${\text{CuSO}}_{\text{4}}$ that react with given mass of Zinc metal has to be calculated.

Concept introduction:

Precipitation reaction:

The precipitate is formed, when the two solutions mixed together is called precipitation reaction.

The mass of the precipitate is depends on the reactant masses.

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of compound is given by the ratio between taken mass of the compound and molar mass of the compound.

$\text{Mole}\text{=}\frac{\text{Massof}\text{the}\text{compound}}{\text{Molar}\text{mass}\text{of}\text{the}\text{compound}}$

Volume:

The volume of the solution is given by ratio between concentration of solution and mole of the solute present in the solution.

$\text{Volume}\text{(L)=}\frac{\text{Mole}}{\text{Concentration}\text{(M)}}$