Chapter 4, Problem 4.53QP

Interpretation Introduction

Interpretation:

Mass of $Ba{(OH)}_{2.}.8H_{2}O$ that is required to male $500mL$ of a solution has to be calculated.

Concept introduction:

 Mole:

 The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

 $\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

 $\text{Molarity = }\frac{\text{No}\text{. of moles of solute}}{\text{Volume of solution in L}}$

 Mass:

 The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

 $\text{Mass}\text{=}\text{Mole}\text{×}\text{Molar}\text{mass}$