Chapter 4, Problem 4.54QP

Interpretation Introduction

Interpretation:

Preparation of $\text{250 mL}$$\text{0}\text{.707}\text{M}$${\text{NaNO}}_{\text{3}}$ solution has to be explained.

Concept introduction:

$Molarityofthesolution=\frac{Molesofsolute}{Volumeinliter}$

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

The mass of compound is given by the multiplication of mole of the compound and molar mass of the compound in gram.

$\text{Mass}\text{=}\text{Mole×}\text{Molar}\text{mass}$