Mass of the precipitate after the solutions are mixed has to be calculated. Concept introduction: Precipitation reaction: When the two solutions mixed together and resultant compound settles down in the solution as a precipitate is called precipitation reaction. Mole: The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is, Mole = Concentration (M)× volume (L) Molarity = No . of moles of solute Volume of solution in L Mass: The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute. Mass = Mole × Molar mass

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Chapter 4, Problem 4.96QP

(a)

Interpretation Introduction

Interpretation:

Mass of the precipitate after the solutions are mixed has to be calculated.

Concept introduction:

Precipitation reaction:

When the two solutions mixed together and resultant compound settles down in the solution as a precipitate is called precipitation reaction.

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

Mole = Concentration (M)× volume (L)

Molarity = No. of moles of soluteVolume of solution in L

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass = Mole × Molar mass

(b)

Interpretation Introduction

Interpretation:

Concentration of the final solution has to be calculated.

Concept introduction:

Precipitation reaction:

When the two solutions mixed together and resultant compound settles down in the solution as a precipitate is called precipitation reaction.

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

Mole = Concentration (M)× volume (L)

Molarity = No. of moles of soluteVolume of solution in L

Mass:

The mass of solute present in the solution is given by multiplication of mole and molar mass of the solute.

Mass = Mole × Molar mass

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