Female life expectancy . The life expectancy for females born during 1980 - 1985 was approximately 77.6 years. This grew to 78 years during 1985 - 1990 and to 78.6 years during 1990-1995. Construct a model for this data by finding a quadratic equation whose graph passes through the points 0.77 , 6 , 5 , 78 and 10.78 , 6 . Use this model to estimate the life expectancy for females born between 1995 and 2000 and for those born between 2000 and 2005 .
Female life expectancy . The life expectancy for females born during 1980 - 1985 was approximately 77.6 years. This grew to 78 years during 1985 - 1990 and to 78.6 years during 1990-1995. Construct a model for this data by finding a quadratic equation whose graph passes through the points 0.77 , 6 , 5 , 78 and 10.78 , 6 . Use this model to estimate the life expectancy for females born between 1995 and 2000 and for those born between 2000 and 2005 .
Solution Summary: The author explains the quadratic equation for the data of life expectancy for females.
Female life expectancy. The life expectancy for females born during
1980
-
1985
was approximately
77.6
years. This grew to
78
years during
1985
-
1990
and to
78.6
years during 1990-1995. Construct a model for this data by finding a quadratic equation whose graph passes through the points
0.77
,
6
,
5
,
78
and
10.78
,
6
. Use this model to estimate the life expectancy for females born between
1995
and
2000
and for those born between
2000
and
2005
.
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
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Assume that a company is considering purchasing a machine for $50,000 that will have a five-year useful life and a $5,000 salvage value. The
machine will lower operating costs by $17,000 per year. The company's required rate of return is 15%. The net present value of this investment
is closest to:
Click here to view Exhibit 12B-1 and Exhibit 12B-2, to determine the appropriate discount factor(s) using the tables provided.
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Multiple Choice
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$6,984.
$11,859.
$22,919.
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7. [10 marks]
Let G
=
(V,E) be a 3-connected graph. We prove that for every x, y, z Є V, there is a
cycle in G on which x, y, and z all lie.
(a) First prove that there are two internally disjoint xy-paths Po and P₁.
(b) If z is on either Po or P₁, then combining Po and P₁ produces a cycle on which
x, y, and z all lie. So assume that z is not on Po and not on P₁. Now prove that
there are three paths Qo, Q1, and Q2 such that:
⚫each Qi starts at z;
• each Qi ends at a vertex w; that is on Po or on P₁, where wo, w₁, and w₂ are
distinct;
the paths Qo, Q1, Q2 are disjoint from each other (except at the start vertex
2) and are disjoint from the paths Po and P₁ (except at the end vertices wo,
W1, and w₂).
(c) Use paths Po, P₁, Qo, Q1, and Q2 to prove that there is a cycle on which x, y, and
z all lie. (To do this, notice that two of the w; must be on the same Pj.)
Chapter 4 Solutions
Pearson eText for Finite Mathematics for Business, Economics, Life Sciences, and Social Sciences -- Instant Access (Pearson+)
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