In Problems 45 - 50 , explain why the system cannot the solved by matrix inverse methods. Discuss methods that could be used and then solve the system. x 1 − 3 x 2 − 2 x 3 = − 1 − 2 x 1 + 7 x + 2 3 x 3 = 3
In Problems 45 - 50 , explain why the system cannot the solved by matrix inverse methods. Discuss methods that could be used and then solve the system. x 1 − 3 x 2 − 2 x 3 = − 1 − 2 x 1 + 7 x + 2 3 x 3 = 3
Solution Summary: The author explains that the matrix inverse method cannot be used to solve the system. The given equation is not a square matrix, there are three unknown variables and just two equations.
In Problems
45
-
50
, explain why the system cannot the solved by matrix inverse methods. Discuss methods that could be used and then solve the system.
x
1
−
3
x
2
−
2
x
3
=
−
1
−
2
x
1
+
7
x
+
2
3
x
3
=
3
A function is defined on the interval (-π/2,π/2) by this multipart rule:
if -π/2 < x < 0
f(x) =
a
if x=0
31-tan x
+31-cot x
if 0 < x < π/2
Here, a and b are constants. Find a and b so that the function f(x) is continuous at x=0.
a=
b= 3
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a.
f(x) = (x + 4x4) 5,
a = -1
lim f(x)
X--1
=
lim
x+4x
X--1
lim
X-1
4
x+4x
5
))"
5
))
by the power law
by the sum law
lim (x) + lim
X--1
4
4x
X-1
-(0,00+(
Find f(-1).
f(-1)=243
lim (x) +
-1 +4
35
4 ([
)
lim (x4)
5
x-1
Thus, by the definition of continuity, f is continuous at a = -1.
by the multiple constant law
by the direct substitution property
Chapter 4 Solutions
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