Problems 85 - 88 require the use of a graphing calculator or a computer. Use the 5 × 5 encoding matrix C given below. Form a matrix with 5 rows and as many columns as necessary to accommodate the message. C = 1 0 1 0 1 0 1 1 0 3 2 1 1 1 1 0 0 1 0 2 1 1 1 2 1 Cryptography. The following message was encoded with matrix C . Decode this message: 25 75 55 35 50 43 83 54 60 53 25 13 59 9 53 15 35 40 15 45 33 60 60 36 51 15 7 37 0 22
Problems 85 - 88 require the use of a graphing calculator or a computer. Use the 5 × 5 encoding matrix C given below. Form a matrix with 5 rows and as many columns as necessary to accommodate the message. C = 1 0 1 0 1 0 1 1 0 3 2 1 1 1 1 0 0 1 0 2 1 1 1 2 1 Cryptography. The following message was encoded with matrix C . Decode this message: 25 75 55 35 50 43 83 54 60 53 25 13 59 9 53 15 35 40 15 45 33 60 60 36 51 15 7 37 0 22
Solution Summary: The author calculates the hidden message with the use of a graphing calculator and the 5times 5 encoding matrix C.
Problems
85
-
88
require the use of a graphing calculator or a computer. Use the
5
×
5
encoding matrix
C
given below. Form a matrix with
5
rows and as many columns as necessary to accommodate the message.
A function is defined on the interval (-π/2,π/2) by this multipart rule:
if -π/2 < x < 0
f(x) =
a
if x=0
31-tan x
+31-cot x
if 0 < x < π/2
Here, a and b are constants. Find a and b so that the function f(x) is continuous at x=0.
a=
b= 3
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a.
f(x) = (x + 4x4) 5,
a = -1
lim f(x)
X--1
=
lim
x+4x
X--1
lim
X-1
4
x+4x
5
))"
5
))
by the power law
by the sum law
lim (x) + lim
X--1
4
4x
X-1
-(0,00+(
Find f(-1).
f(-1)=243
lim (x) +
-1 +4
35
4 ([
)
lim (x4)
5
x-1
Thus, by the definition of continuity, f is continuous at a = -1.
by the multiple constant law
by the direct substitution property
Chapter 4 Solutions
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