Explanation y = x + x − 1 ( x > 0 ) Critical point definition Critical points are point where the function is defined are its derivates is zero or undefined Find where f ’ ( x ) is equal to zero or undefined f ' ( x ) = 1 − 1 x 2 d d x ( x + x − 1 ) Apply the sum difference rule ( f ± g ) ' = f ' ± g ' = d d x ( x ) + d d x ( x − 1 ) d d x ( x ) = 1 d d x ( x ) Apply the common derivative : d d x ( x ) = 1 =1 d d x ( x − 1 ) = − 1 x 2 = 1 − 1 x 2 Solve 1 − 1 x 2 = 0 : x = 1 , x = − 1 1 − 1 x 2 = 0 Multiply both sides by x 2 1 ⋅ x 2 − 1 x 2 x 2 = 0 ⋅ x 2 x 2 − 1 = 0 Add 1 to both sides x 2 − 1 + 1 = 0 + 1 Simplify x 2 = 1 For x 2 = f ( a ) the solutions are

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.3, Problem 39E

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y=x+x−1 (x>0)

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Chapter 4.3, Problem 38E

Chapter 4.3, Problem 40E

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Chapter 4 Solutions

CALCULUS (CLOTH)

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y = x + x − 1 ( x &gt; 0 )

Solution Summary: The author explains how to determine the value of y=x+x-1-(x>0).

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y=x+x−1 (x>0)

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Chapter 4 Solutions

y = x + x − 1 ( x > 0 )