Explanation Given: f ( x ) = x − 1 − x − 2 We know that the critical points are the points at which the derivatives of the function become zero or undefined. Here, the given function is f ( x ) = x − 1 − x − 2 Differentiating the above function with respect to x, we get f ' ( x ) = d d x ( x − 1 − x − 2 ) = d d x ( 1 x − 1 x 2 ) = − 1 x 2 − ( − 2 x 3 ) f ' ( x ) = − 1 x 2 + 2 x 3 To find out the critical points, we equate the above equation to zero

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ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.2, Problem 7E

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To find all the critical points of the function f(x)=x−1−x−2

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Chapter 4.2, Problem 6E

Chapter 4.2, Problem 8E

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4 Consider f(x) periodic function with period 2, coinciding with (x) = -x on the interval [,0) and being the null function on the interval [0,7). The Fourier series of f: (A) does not converge in quadratic norm to f(x) on [−π,π] (B) is pointwise convergent to f(x) for every x = R П (C) is in the form - 4 ∞ +Σ ak cos(kx) + bk sin(kx), ak ‡0, bk ‡0 k=1 (D) is in the form ak cos(kx) + bk sin(kx), ak 0, bk 0 k=1

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Chapter 4 Solutions

CALCULUS (CLOTH)

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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To find all the critical points of the function f ( x ) = x − 1 − x − 2

Solution Summary: The author explains that the critical points are the points at which the derivatives of the function become zero or undefined.

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To find all the critical points of the function f(x)=x−1−x−2

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Chapter 4 Solutions