Explanation Given: y = x 3 − 2 x 2 + 3 Formula Used: Calculation: We know that the inflection points are the points at which the sign of the second derivatives of the function changes. Here, the given function is y = x 3 − 2 x 2 + 3 Differentiating the above function, we get d y d x = 3 x 2 − 4 x To find out the critical points, we equate the above equation to zero. i.e. 3 x 2 − 4 x = 0 On solving this, we get x = 0 and x = 4 3 Therefore, the critical points of the given functionoccur at x = 0 and x = 4 3 . Now we second derivative to find the inflection points. d 2 y d x 2 = 6 x − 4 To find out the inflection points, we equate the above equation to zero

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Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4, Problem 47CRE

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To find the points of inflection for the function, y=x3−2x2+3.

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Chapter 4, Problem 46CRE

Chapter 4, Problem 48CRE

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Chapter 4 Solutions

CALCULUS (CLOTH)

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To find the points of inflection for the function, y = x 3 − 2 x 2 + 3 .

Solution Summary: The author explains that the inflection points are the points at which the sign of the second derivatives of a function changes.

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Chapter 4 Solutions