Explanation Given: y = 4 sin 3 θ − 3 cos 2 θ , [ 0 , 2 π ] 4 sin 3 ( θ ) − 3 cos 2 ( θ ) , 0 ≤ θ ≤ 2 π : ? = 0 , ? = π 2 , θ = π , θ = 7 π 6 , θ = 3 π 2 , θ = 11 π 6 , θ = 2 π Find where f ' ( x ) is equal to zero or undefined ( θ ) = 3 ( 4 sin 2 ( θ ) cos ( θ ) + sin ( 2 θ ) ) d d θ ( 4 sin 3 ( θ ) − 3 cos 2 ( θ ) ) = d d θ ( 4 sin 3 ( θ ) ) − d d ? ( 3 cos 2 ( θ ) ) d d θ ( 4 sin 3 ( θ ) ) = 12 sin 2 ( θ ) cos ( θ ) d d θ ( 4 sin 3 ( θ ) ) = 4 d d θ ( sin 3 ( θ ) ) θ = 0 , ? = π 2 , θ = π , θ = 7 π 6 , θ = 3 π 2 , θ = 11 π 6 , θ = 2 π Apply the chain rule d f ( u ) d x = d f d u ⋅ d u d x f = u 3 , u = sin ( θ ) = 4 d d u ( u 3 ) d d θ ( sin ( θ )

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.2, Problem 50E

To determine

y=4sin3θ−3cos2θ, [0,2π]

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Chapter 4.2, Problem 49E

Chapter 4.2, Problem 51E

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Chapter 4 Solutions

CALCULUS (CLOTH)

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y = 4 sin 3 θ − 3 cos 2 θ , [ 0 , 2 π ]

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y=4sin3θ−3cos2θ, [0,2π]

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Chapter 4 Solutions