Explanation Given info: R ( t ) = t t 2 + t + 1 on [ 0 , 3 ] Calculation : We need to derivative of the to find the critical points R ' ( t ) = ( t 2 + t + 1 ) ( 1 ) − t ( 2 t + 1 ) ( t 2 + t + 1 ) 2 Therefore the only critical points will be those values of x which make the derivative zero. So, we must solve. R ' ( t ) = 0 ( t 2 + t + 1 ) ( 1 ) − t ( 2 t + 1 ) ( t 2 + t + 1 ) 2 = 0 ( t 2 + t + 1 − 2 t

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4, Problem 32CRE

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Find the extreme value on the interval on [0,3]

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Chapter 4, Problem 31CRE

Chapter 4, Problem 33CRE

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Chapter 4 Solutions

CALCULUS (CLOTH)

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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Find the extreme value on the interval on [ 0 , 3 ]

Solution Summary: The author explains how to determine the extreme value of the theorem on the interval on [0,3].

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Chapter 4 Solutions