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The reason for allocating the hours of study to different courses by the student to maximize his or her grades out of the following reasons:
The grade in each course is the same.
The marginal product of a study hour in each course is zero.
The marginal product of a study hour in each course is equal, although not necessarily equal to zero.
The average product of an hour's study in each course is equal.
The number of hours spent in study for each course is equal.
If the number of hours for study is fixed and the relationship between hours of study and the final grade for each course is certain. The grade average is given on a scale of
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Chapter 4 Solutions
Student Solutions Manual for Waner/Costenoble's Applied Calculus, 7th
- Forces of 9 pounds and 15 pounds act on each other with an angle of 72°. The magnitude of the resultant force The resultant force has an angle of pounds. * with the 9 pound force. The resultant force has an angle of with the 15 pound force. It is best to calculate each angle separately and check by seeing if they add to 72°.arrow_forward= Let (6,2,-5) and = (5,4, -6). Compute the following: บี.บี. บี. นี = 2 −4(u. v) = (-4). v= ū. (-40) (ū. v) v =arrow_forwardLet ā-6+4j- 1k and b = 7i8j+3k. Find a. b.arrow_forward
- Find the volume of the parallelepiped determined by the vectors a = (3, 5, −1), ☎ = (0, 3, 1), c = (2,4,1).arrow_forwardFind the area of a triangle PQR, where P = (-5,6, -1), Q = (1, -3, -2), and R = (-5, -1,4)arrow_forward17. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.2.050. Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) du 4√3- -4² Need Help? Read It SUBMIT ANSWER 18. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.2.051. Evaluate the integral. (Use C for the constant of integration.) - 49 dx x² +3 Need Help? Read It Watch It SUBMIT ANSWER 19. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.2.057. Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) 25+ x2 dxarrow_forward
- Let (5,3,-7) and = (2, -3, -6). = Compute the following: u× u = -4(u xv) ux (-4v) (+v) × v=arrow_forwardLet a = (4, -2, -7) and 6 = (2,5, 3). (ã − ò) × (ã + b) =arrow_forwardUse the graph of the function y = f (x) to find the value, if possible. f(x) 8 7 6 Q5 y 3 2 1 x -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 -1 -2 -3 -4 -5 -6 -7 -8+ Olim f(z) x-1+ O Limit does not exist.arrow_forward
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