Velocity The height of a basketball thrown by Chris Paul on Neptune is given by h ( t ) = v 0 t − 5.6 t 2 meters, where t is time in seconds after he throws the ball up at v 0 m/sec 6 . a. When the ball reaches its highest point, h ′ ( t ) mustequal zero (see Exercises 95). Given a formula for the value of t when this occurs. b. How fast would he need to throw it up in order for it to reach its highest point in half a second? How high would it get?
Velocity The height of a basketball thrown by Chris Paul on Neptune is given by h ( t ) = v 0 t − 5.6 t 2 meters, where t is time in seconds after he throws the ball up at v 0 m/sec 6 . a. When the ball reaches its highest point, h ′ ( t ) mustequal zero (see Exercises 95). Given a formula for the value of t when this occurs. b. How fast would he need to throw it up in order for it to reach its highest point in half a second? How high would it get?
Solution Summary: The author explains the formula for the value of t when hprime (t)=0 where height of basketball thrown by Chris Paul on Neptune is given by function.
The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.
The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.
4. Use method of separation of variable to solve the following wave equation
მłu
J²u
subject to
u(0,t) =0, for t> 0,
u(л,t) = 0, for t> 0,
=
t> 0,
at²
ax²'
u(x, 0) = 0,
0.01 x,
ut(x, 0) =
Π
0.01 (π-x),
0
Chapter 4 Solutions
Student Solutions Manual for Waner/Costenoble's Applied Calculus, 7th
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Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY