Chapter 4, Problem 66E

Interpretation Introduction

Interpretation:

The volume of 0.0521M ${\text{Ba(OH)}}_{\text{2}}$ should be calculated which is needed to neutralize 14.20 mL of 0.141M ${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$ .

Concept Introduction:

Number of moles is equal to the ratio of given mass to the molar mass.

The mathematical expression is given by:

Number of moles = $\frac{\text{given mass}}{\text{molar mass}}$

Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.

The mathematical expression is given by:

Molarity = $\frac{\text{moles of solute }}{\text{volume of solution in liters}}$

A solution of salt of metal when reacts with other solution to give products, the formula which is used to find the volume of either solution is given by:

  ${\text{M}}_{\text{1}}{\text{V}}_{\text{1}}{\text{=M}}_{\text{2}}{\text{V}}_{\text{2}}$

Where, M₁ and M₂ are molarity of the solution

V₁ and V₂ are volume of the solution