Chapter 4, Problem 4.76QE

Interpretation Introduction

Interpretation:

The mass of Magnesium hydroxide has to be calculated, that is formed in the reaction of $\text{1}\text{.2 L of a 5}\text{.5}\text{M}$ solution of Sodium hydroxide and excess Magnesium nitrate.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Mole: Dividing taken mass substance by molar mass of substance.

  $\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$