Chapter 4, Problem 4.69QE

Interpretation Introduction

Interpretation:

The gram mass of Sodium hydroxide has to be calculated, that is needed to react with $\text{100}\text{.0 mL of 3}{\text{.13 M H}}_{\text{2}}{\text{SO}}_{\text{4}}$.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Mole: Dividing taken mass substance by molar mass of substance.

  $\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$