Chapter 4, Problem 4.73QE

Interpretation Introduction

Interpretation:

The molar concentration of $\text{135 mL}\text{of}\text{HCl}$ solution has to be calculated, that is completely react with $\text{2}\text{.55 g Ba}{\left(\text{OH}\right)}_{\text{2}}$.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Mole: Dividing taken mass substance by molar mass of substance.

  $\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$