Chapter 4, Problem 4.61QE

(a)

Interpretation Introduction

Interpretation:

The number of moles of solute in $\text{1}\text{.33 L of a 0}{\text{.211 M AgNO}}_{\text{3}}$ solution has to be calculated.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

(b)

Interpretation Introduction

Interpretation:

The number of moles of solute in $\text{1000 mL of a 0}{\text{.00113 M CaCl}}_{\text{2}}$ solution has to be calculated.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$