Fundamentals Of Engineering Thermodynamics
9th Edition
ISBN: 9781119391388
Author: MORAN, Michael J., SHAPIRO, Howard N., Boettner, Daisie D., Bailey, Margaret B.
Publisher: Wiley,
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Chapter 4, Problem 4.47CU
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Chapter 4 Solutions
Fundamentals Of Engineering Thermodynamics
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
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- Derive an expression for the change in entropy of the universe. 7arrow_forwardA spring-conditioned cylinder-piston device contains 0.25kg of air and operates under the following thermodynamic cycle:1 -> 2: In state 1, P_1 = 200kPa and V_1 = 0.25m ^ 3. The compressed spring is released and the air is compressed, until the spring no longer stores energy and the piston simply rests on the stops: P_2 = 300kPa and V_2 = 0.10m ^ 3.2 -> 3 After compression the heat is removed and the pressure drops to 100kPa in state 3.3 -> 1: Heat is added, the spring is compressed, and the air expands to state 1. a) Make a diagram of the process and trajectories.b) Determine the air temperature in the 3 states.c) Calculate the work from state 1 to 2.d) Calculate the work from state 3 to 1.e) Calculate the total work of the cycle and who performs it.arrow_forward1-kg copper part, initially at Tc= 400 degrees C, is plunged into a tank containing 5 kg of liquid water, initially at Tw= 30 degrees C. the copper part and water can be modeled as incompressible with specific heats cc= 0.385 kJ/kgK and cw= 4.2 kJ/kgK, respectively. use the copper part and water as the system. ignore heat transfer between the system and its surroundings. determine the amount of entropy produced within the tank, in kJ/K.arrow_forward
- Ten lbm per min of fluid is handled in a reversible steady flow manner by a thermodynamic system located where the local g = 32 ft/s2. For the liquid, p1 = 20 psia, p2 = 80 psia, ρ1= 1.6 lbm/ft3, ρ2 = 0.32 lbm/ft3, v1 = 400 ft/s, v2 = 600 ft/s, u1 = 130 BTU/lbm, u2 = 130 BTU/lbm. During passage through the system, the fluid rejects 50 BTU/s as heat and rises 175 ft in elevation. During passage through the system, the fluid rejects 50 Btu/s as heat and rises 175 ft in elevation. Determine the work in the system, in BTU. Select one: a. – 675.2 b. – 781.8 c. 892.6 d. 987.4arrow_forwardTen lbm per min of fluid is handled in a reversible steady flow manner by a thermodynamic system located where the local g = 32 ft/s2. For the liquid, p1 = 20 psia, p2 = 80 psia, ρ1= 1.6 lbm/ft3, ρ2 = 0.32 lbm/ft3, v1 = 400 ft/s, v2 = 600 ft/s, u1 = 130 BTU/lbm, u2 = 130 BTU/lbm. During passage through the system, the fluid rejects 50 BTU/s as heat and rises 175 ft in elevation. What is the change in kinetic energy in BTU? Select one: a. 23.56 b. 29.34 c. 34.56 d. 39.95arrow_forwardTen lbm per min of fluid is handled in a reversible steady flow manner by a thermodynamic system located where the local g = 32 ft/s2. For the liquid, p1 = 20 psia, p2 = 80 psia, ρ1= 1.6 lbm/ft3, ρ2 = 0.32 lbm/ft3, v1 = 400 ft/s, v2 = 600 ft/s, u1 = 130 BTU/lbm, u2 = 130 BTU/lbm. During passage through the system, the fluid rejects 50 BTU/s as heat and rises 175 ft in elevation. Determine change in potential energy in BTU Select one: a. 2.237 b. 2.575 c. 5.642 d. 7.237arrow_forward
- A perfect gas has a value of R = 316 J/kg-K and k = 1.26. If 21 kJ of heat are added to 2.5 kg of this gas during an isometric process when the initial temperature is 32 deg. C, determine: (a) the final temperature in deg. C 312 292 39 (b) the change in enthalpy in kJ 28.46 26.46 23.46 (c) the change in entropy in kJ/K 0.087 0.167 0.067arrow_forwardThermodynamics explain the application of the first law of thermodynamics to appropriate systems.arrow_forwardSteam flows through a nozzle at mass flow rate of m= 0.1kg/s with a heat loss of 5 kW. The enthalpies at inlet and exit are 2500 kJ/kg and 2350 kJ/kg, respectively. Assuming negligible velocity at inlet (C, - 0), the velocity (C,) of steam (in m/s) at the nozzle exit %3D is (correct to two decimal places) å= 5 KW h=2350 kJ/kg h, 2500 kJ/kg C, -0 -0.1 kg/sarrow_forward
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