(a) Interpretation: The name of the given binary ionic compound is to be stated by adding the endings - o u s and - i c to indicate the lower and higher ionic charges of the metal ion in each pair of compound. Concept introduction: Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion. The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Question

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Answer 1

Question

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Conclusion

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

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Answer 2

Question

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Conclusion

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

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Answer 3

Question

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Conclusion

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

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Answer 4

Question

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Conclusion

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

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Answer 5

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Conclusion

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Answer 6

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Answer 7

Chapter 4, Problem 4.33E

Interpretation Introduction

(a)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Answer 8

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CrCl2$ and $CrCl3$ . Both the compounds contain chromium as a metal and chlorine as a non-metal. The chromium can exists as $Cr2+$ and $Cr3+$ ions and chlorine as $Cl−$ ions in ionic form. The ending $-ous$ is used for $Cr2+$ while endings $-ic$ is used for $Cr3+$ . The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Answer 13

Conclusion

The name of the binary ionic compound $CrCl2$ is chromous chloride and $CrCl3$ is chromic chloride.

Answer 14

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Answer 15

Interpretation Introduction

(b)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Answer 16

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $CoS$ and $Co2S3$ . Both the compounds contain cobalt as a metal and sulfur as a non-metal. The cobalt can exists as $Co2+$ and $Co3+$ ions and sulfide as $S2−$ ions in ionic form. The endings $-ous$ is used for $Co2+$ while endings $-ic$ is used for $Co3+$ . The suffix –ide is added after “sulf” of sulfur to obtain sulfide.

Hence, the name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Answer 21

Conclusion

The name of the binary ionic compound $CoS$ is cobaltous sulfide and $Co2S3$ is cobaltic sulfide.

Answer 22

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Answer 23

Interpretation Introduction

(c)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Answer 24

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The binary ionic compounds are $FeO$ and $Fe2O3$ . Both the compounds contain iron as a metal and oxygen as a non-metal. The iron can exists as $Fe2+$ and $Fe3+$ ions and oxygen as $O2−$ ion in ionic form.

The endings $-ous$ is used for $Fe2+$ while endings $-ic$ is used for $Fe3+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide.

Hence, the name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Answer 29

Conclusion

The name of the binary ionic compound $FeO$ is ferrous oxide and $Fe2O3$ is ferric oxide.

Answer 30

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.

Hence, the name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Conclusion

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Answer 31

Interpretation Introduction

(d)

Interpretation:

The name of the given binary ionic compound is to be stated by adding the endings $-ous$ and $-ic$ to indicate the lower and higher ionic charges of the metal ion in each pair of compound.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

The naming of non-metal ions is done by the addition of suffix –ide at the end of the element’s name. The naming of binary ionic compound is represented by the name of metal followed by the name of non-metal.

Answer 32

Expert Solution

Answer to Problem 4.33E

The name of the binary ionic compound $PbCl2$ is plumbous chloride and $PbCl4$ is plumbic chloride.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

The non-English names are used to indicate the lower and higher ionic charges of the metal ion. The ending $-ous$ is added to an ion that has lower charge and $-ic$ is added to an ion that has higher charge.

The given binary ionic compounds are $PbCl2$ and $PbCl4$ . Both the compounds contain lead as a metal and chlorine as a non-metal. The lead can exists as $Pb2+$ and $Pb4+$ and chlorine as $Cl−$ ion in ionic form.

The non-English root for lead $(Pb)$ is $plumb-$ . The endings $-ous$ is used for $Pb2+$ while endings $-ic$ is used for $Pb4+$ . The suffix –ide is added after “ox” of oxygen to obtain oxide. The suffix –ide is added after “chlor” of chlorine to obtain chloride.