(a) Interpretation: The number of positive ions and negative ions contained in 1.00 mol of given compound is to be calculated. Concept introduction: Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Al3+$ cations is $=1×6.02×1023=6.02×1023$

The number of $Cl−$ anions is $=3×6.02×1023=18.06×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

reciprocal lattices rotates along with the real space lattices of the crystal. true or false?

Deducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Check

Predict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. L

Answer 2

Question

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Al3+$ cations is $=1×6.02×1023=6.02×1023$

The number of $Cl−$ anions is $=3×6.02×1023=18.06×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Al3+$ cations is $=1×6.02×1023=6.02×1023$

The number of $Cl−$ anions is $=3×6.02×1023=18.06×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Al3+$ cations is $=1×6.02×1023=6.02×1023$

The number of $Cl−$ anions is $=3×6.02×1023=18.06×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Al3+$ cations is $=1×6.02×1023=6.02×1023$

The number of $Cl−$ anions is $=3×6.02×1023=18.06×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Answer 6

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Answer 7

Chapter 4, Problem 4.43E

Interpretation Introduction

(a)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer 8

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The given compound is $Na2O$ .

One mole of $Na2O$ compound contains two moles of $Na+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Na+$ cations is $=2×6.02×1023=12.04×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Answer 13

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $Na2O$ is $12.04×1023$ and $6.02×1023$ respectively.

Answer 14

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Answer 15

Interpretation Introduction

(b)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer 16

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The given compound is $FeO$ .

One mole of $FeO$ compound contains one mole of $Fe2+$ cation and one mole of $O2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Fe2+$ cations is $=1×6.02×1023=6.02×1023$

The number of $O2−$ anions is $=1×6.02×1023=6.02×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Answer 21

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $FeO$ is $6.02×1023$ and $6.02×1023$ respectively.

Answer 22

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Answer 23

Interpretation Introduction

(c)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer 24

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The given compound is $PbS2$ .

One mole of $PbS2$ compound contains one mole of $Pb4+$ cation and two moles of $S2−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Pb4+$ cations is $=1×6.02×1023=6.02×1023$

The number of $S2−$ anions is $=2×6.02×1023=12.04×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Answer 29

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $PbS2$ is $6.02×1023$ and $12.04×1023$ respectively.

Answer 30

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,

The number of $Al3+$ cations is $=1×6.02×1023=6.02×1023$

The number of $Cl−$ anions is $=3×6.02×1023=18.06×1023$

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Conclusion

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Answer 31

Interpretation Introduction

(d)

Interpretation:

The number of positive ions and negative ions contained in $1.00 mol$ of given compound is to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer 32

Expert Solution

Answer to Problem 4.43E

The number of positive ions and negative ions contained in $1.00 mol$ of $AlCl3$ is $6.02×1023$ and $18.06×1023$ respectively.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

The given compound is $AlCl3$ .

One mole of $AlCl3$ compound contains one mole of $Al3+$ cation and three moles of $Cl−$ anion. The number of atoms present in one mole is equal to Avogadro’s number $(6.02×1023)$ . Therefore,