The volume (L) of 2.050 M copper ( II ) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is to be calculated. Concept introduction: Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, the amount of solute remains fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed. The expression to relate the molarity of a concentrated and dilute solution is: M 1 V 1 = M 2 V 2 (1) Here, M 1 is the molarity of the dilute solution. V 1 is the volume of dilute solution. M 2 is the molarity of the concentrated solution. V 2 is the volume of the concentrated solution.
The volume (L) of 2.050 M copper ( II ) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is to be calculated. Concept introduction: Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, the amount of solute remains fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed. The expression to relate the molarity of a concentrated and dilute solution is: M 1 V 1 = M 2 V 2 (1) Here, M 1 is the molarity of the dilute solution. V 1 is the volume of dilute solution. M 2 is the molarity of the concentrated solution. V 2 is the volume of the concentrated solution.
The volume (L) of 2.050Mcopper(II)nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543M solution is to be calculated.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, the amount of solute remains fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to relate the molarity of a concentrated and dilute solution is:
M1V1=M2V2 (1)
Here,
M1 is the molarity of the dilute solution.
V1 is the volume of dilute solution.
M2 is the molarity of the concentrated solution.
V2 is the volume of the concentrated solution.
(b)
Interpretation Introduction
Interpretation:
Volume (L) of 1.63M calcium chloride that must be diluted with water to prepare 350 mL of a 2.86×10−2M chloride ion solution is to be calculated.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, the amount of solute remains fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to relate the molarity of a concentrated and dilute solution is:
M1V1=M2V2 (1)
Here,
M1 is the molarity of the dilute solution.
V1 is the volume of dilute solution.
M2 is the molarity of the concentrated solution.
V2 is the volume of the concentrated solution.
(c)
Interpretation Introduction
Interpretation:
The final volume (L) of a 0.0700M solution prepared by diluting 18.0 mL of 0.155M lithium carbonate with water is to be calculated.
Concept introduction:
Dilution is the process of converting a concentrated solution into a dilute solution by adding the solvent. In the resultant solution, the amount of solute remains fixed but the volume of the solution increases. The moles of solute before and after dilution remain fixed.
The expression to relate the molarity of a concentrated and dilute solution is:
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