Chapter 4, Problem 4.1P

Interpretation Introduction

To determine:

The molarity of sucrose in the drink.

Answer to Problem 4.1P

Solution:

The molarity of sucrose in the drink is $\text{0}\text{.376}\text{M}$.

Explanation of Solution

Given:

Volume of tea beverage $=355\text{ml}$

Mass of sucrose $=43.0\text{g}$

Formula used:

Molarity $=\frac{\text{number of moles of solute}}{\text{volume of solution in liter}}$

Calculation:

Molar mass of sucrose $\left({\text{C}}_{12}{\text{H}}_{22}{\text{O}}_{11}\right)$ can be calculated as:

  $\text{12×12}\text{.01 g/mol +22×}\left(\text{1}\text{.008}\text{g/mol}\right)\text{+11×(16}\text{.00}\text{g/mol)}$

  $\text{=342}\text{.296}\text{g/mol}$

Now,
Number of moles

  $\begin{array}{l}=\frac{43.0\text{g}}{342.296\text{g/mol}}\\ =0.126\text{mole}\end{array}$

Molarity $\text{=}\frac{\text{0}\text{.126}\text{mol}}{\text{335}\text{ml×}\frac{\text{1}\text{L}}{\text{1000}\text{ml}}}$

  $\text{=0}\text{.376}\text{M}$

Therefore, the molarity of sucrose is $\text{0}\text{.376}\text{M}$

Conclusion

The molarity of sucrose is $\text{0}\text{.376}\text{M}$.

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