Explanation We need to calculate the amount of MnO 4 - that was used during the titration: To complete the reaction 15.05 mL of 0.0247 M KMnO 4 is required. One mole of KMnO 4 releases 1 mole of MnO 4 - ions. 15 .05 mL × 1L 1000mL × 0 .0247 mol KMnO 4 1L × 1 mol MnO 4 - 1 mol KMnO 4 = 0 .000372 mol MnO 4 - Therefore, the amount of MnO 4 - that was used during the titration is 0.000372 mol MnO 4-. Now, we can relate this value to the moles of H+ from oxalic acid in the sample using the stoichiometry of the reaction between oxalic acid and the permanganate ion: 0 .000372 mol MnO 4 - × 5 mol oxalic acid 2 mol MnO 4 - × 2 mol H + 1 mol oxalic acid = 0 .00186 mol H + . We can calculate the mass of oxalic acid using the molar mass of oxalic acid. 0 .000186 mol H + × 1 mol oxalic acid 1 mol H + × 90 .0 g oxalic acid 1 mol oxalic acid = 0 .167 g oxalic acid . Now, we need to calculate the total number of moles of H+ in the solution. 27 .15 mL × 1 L 1000 mL × 0 .100 mol NaOH 1 L × 1 mol OH - 1 mol NaOH × 1 mol H + 1 mol OH - = 0 .00272 mol H + The total number of moles of H+ in the solution is 0.00272 mol H+ We can calculate the number of moles of H+ that originated from acetic acid, and thus the mass of acetic acid. Mol H + from acetic acid = ( total mol H + ) - ( H + from oxalic acid ) = 0

8th Edition

ISBN: 9780134856230

Author: Robinson

Publisher: PEARSON

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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Chapter 4, Problem 4.145MP

Interpretation Introduction

Interpretation:

The mass percent of each acid in the mixture needs to be determined.

Concept introduction:

Mass generally is described in grams (g) and kilograms (kg). Where W is weight, m is mass, and g is acceleration due to gravity, which is about 9.8 m/s2 on Earth.

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Chapter 4, Problem 4.144MP

Chapter 4, Problem 4.146MP

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Chapter 4 Solutions

CHEMISTRY-TEXT

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The mass percent of each acid in the mixture needs to be determined. Concept introduction: Mass generally is described in grams (g) and kilograms (kg). Where W is weight, m is mass, and g is acceleration due to gravity, which is about 9.8 m/s2 on Earth.

Solution Summary: The author explains that the mass percent of each acid in the mixture needs to be determined. To complete the reaction, 15.05 mL of 0.0247 MnO 4 is required.

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Interpretation: The mass percent of each acid in the mixture needs to be determined. Concept introduction: Mass generally is described in grams (g) and kilograms (kg). Where W is weight, m is mass, and g is acceleration due to gravity, which is about 9.8 m/s2 on Earth.

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Chapter 4 Solutions

Interpretation:

The mass percent of each acid in the mixture needs to be determined.

Concept introduction:

Mass generally is described in grams (g) and kilograms (kg). Where W is weight, m is mass, and g is acceleration due to gravity, which is about 9.8 m/s2 on Earth.