Genetic Analysis: An Integrated Approach (2nd Edition)
Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 4, Problem 30P

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue- flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1 . Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4 . The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.

a. Use the form below to calculate chi square for the 1:2:1 hypothesis of Dr. Sophila.

Chapter 4, Problem 30P, Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They , example  1

b. Use the form below to calculate chi square for the 9:3:4 . hypothesis of Dr. Gans.

Chapter 4, Problem 30P, Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They , example  2

c. What is your conclusion regarding these two genetic hypotheses?

d. Using any of the 100 progeny plants, propose a cross that will verify the conclusion you proposed in part (c). Plants may be self-fertilized, or one plant can be crossed to another. What result will be consistent with the 1:2:1 hypothesis? What result will be consistent with the 9:3:4 . hypothesis?

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A geneticist has two true-breeding strains of mice. Each strain is homozygous for an independently discovered dominant mutation that causes the mice to have no fur. One mutant strain is called “hairless”, and the other strain is called “naked”. The geneticist crosses hairless and naked mice with each other and the F1 offspring all have no fur. When the F1 mice are crossed with each other, the offspring consist of 187 mutant mice with without fur and 13 normal mice with fur. a.      Are the “hairless” and “naked” mutations alleles of the same gene? Give a reason for your answer. b.    Give the genotypic and associated phenotypic ratios of the F2 offspring. (which genotypes in the offspring of the F1 x F1 cross produce fur and which genotypes produce no fur).  In another strain of mice, coat colour is controlled by a single gene with multiple alleles in a dominance series where cream (A1) > agouti (A2) > brown (A3) > black (A4). c. Give the genotypes of two phenotypically…
An individual with the genotype F/f Ÿ• G/g Ÿ• H/h is testcrossed. Among the progeny, the proportions of genotypes from this cross are shown in the following table: a) What gene is in the middle? Type you answer in this box:   b) Calculate the genetic distances (in centimorgans, cM) between: genes g and f: genes f and h: genes g and h: c) What are the genotypes of the two parents? d) Calculate the interference and type your answer here:
All crosses involve many more than one character. So far, only one character has been examined to help simplify the principles involved. Now, two pairs of alleles or two characters will be examined at the same time. In working the following problem, each pair of characteristics is on a different chromosome and will be inherited independently of the other (Principle of Independent Assortment). Problem 1: In garden peas, a homozygous recessive male plant with wrinkled, green seeds is crossed with a plant that is homozygous dominant for round, yellow seeds. Use this information to complete the following: Male phenotype= genotype= gametes= F2 phenotype= genotype = gametes= F, phenotype= F₁ genotype = Female Figure 12.10 Punnett Square for F₁ The F, genotype should be all RrYy. The gametes are formed from various combinations of these alleles. Each gamete must have one R and one Y. For example, the F, male gametes will be RY, Ry, rY, ry. Would the female gametes be the same as the male or…

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Genetic Analysis: An Integrated Approach (2nd Edition)

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