Chapter 4, Problem 14PP

Practice Problem 4.14

Show by a calculation (using the formula $\Delta \text{G}°=-\text{RT}\ln {\text{K}}_{eq}$) that a free-energy difference of $7.6kJmo{l}^{-1}$ between the axial and equatorial forms of methylcyclohexane at 25 °C (with the equatorial form being more stable) does correlate with an equilibrium mixture in which the concentration of the equatorial form is approximately 95%.