Chapter 4, Problem 118A

Interpretation Introduction

Interpretation:

The area of the flattened gold sheet needs to be calculated.

Concept introduction:

The thickness of the flattened sheet is important for the gold foil experiment. Formula to calculated by

$\text{Area}\text{=}\frac{\text{Volume}}{\text{Height}}$

Answer to Problem 118A

The area of the flattened gold sheet is $\text{3}{\text{.3×10}}^{\text{7}}{\text{cm}}^{\text{2}}\text{.}$

Explanation of Solution

Given information:

The volume of the golden block is 1.0cm³ and the thickness of the sheet is $3.0\times {10}^{-8}$ cm.

The area is calculated by the given volume and the thickness of the golden block.

Substitute the given values in formula, $\text{Area}\text{=}\frac{\text{Volume}}{\text{Height}}$

$\text{Area}\text{=}\frac{\text{1}\text{.0}{\text{cm}}^{\text{3}}}{\text{3}{\text{.0×10}}^{\text{-8}}{\text{cm}}^{}}\text{=}\text{3}{\text{.3×10}}^{\text{7}}{\text{cm}}^{\text{2}}$

Conclusion

The area is $\text{3}{\text{.3×10}}^{\text{7}}{\text{cm}}^{\text{2}}\text{.}$