Concept explainers
In a darkened room, a burning candle is placed 1.50 in from a white wall. A lens is placed between the candle and the wall at a location that causes a larger, inverted image to form on the wall. When the lens is in this position, the object distance is p1. When the lens is moved 90.0cm toward the wall, another image of the candle is formed on the wall. From this information, we wish to find p1 and the focal length of the lens. (a) From the lens equation for the first position of the lens, write an equation relating the focal length f of the lens to the object distance p1, with no other variables in the equation. (b) From the lens equation for the second position of the lens, write another equation relating the focal length f of the lens to the object distance p1. (c) Solve the equations in parts (a) and (b) simultaneously to find p1. (d) Use the value in part (c) to find the focal length f of the lens.
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Chapter 35 Solutions
Physics for Scientists and Engineers
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