Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 35.3, Problem 35.5QQ
To determine
The effect on the image position as the object position is changed.
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Chapter 35 Solutions
Physics for Scientists and Engineers
Ch. 35.1 - You are standing approximately 2 m away from a...Ch. 35.2 - You wish to start a fire by reflecting sunlight...Ch. 35.2 - Consider the image in the mirror in Figure 35.14....Ch. 35.3 - Prob. 35.4QQCh. 35.3 - Prob. 35.5QQCh. 35.4 - What is the focal length of a pane of window...Ch. 35.6 - Two campers wish to start a fire during the day....Ch. 35 - (a) Does your bathroom mirror show you older or...Ch. 35 - Two flat mirrors have their reflecting surfaces...Ch. 35 - A periscope (Fig. P35.3) is useful for viewing...
Ch. 35 - Two plane mirrors stand facing each other, 3.00 m...Ch. 35 - An object is placed 50.0 cm from a concave...Ch. 35 - An object is placed 20.0 cm from a concave...Ch. 35 - An object of height 2.00 cm is placed 30.0 cm from...Ch. 35 - Why is the following situation impossible? At a...Ch. 35 - A large hall in a museum has a niche in one wall....Ch. 35 - A concave spherical mirror has a radius of...Ch. 35 - An object 10.0 cm tall is placed at the zero mark...Ch. 35 - You are training to become an opticians assistant....Ch. 35 - A certain Christmas tree ornament is a silver...Ch. 35 - Review. A ball is dropped at t = 0 from rest 3.00...Ch. 35 - You unconsciously estimate the distance to an...Ch. 35 - A convex spherical mirror has a focal length of...Ch. 35 - One end of a long glass rod (n = 1.50) is formed...Ch. 35 - Prob. 18PCh. 35 - Prob. 19PCh. 35 - Figure P35.20 (page 958) shows a curved surface...Ch. 35 - To dress up your dorm room, you have purchased a...Ch. 35 - You are working for a solar energy company. Your...Ch. 35 - An object located 32.0 cm in front of a lens forms...Ch. 35 - An objects distance from a converging lens is 5.00...Ch. 35 - A contact lens is made of plastic with an index of...Ch. 35 - A converging lens has a focal length of 10.0 cm....Ch. 35 - A converging lens has a focal length of 10.0 cm....Ch. 35 - Suppose an object has thickness dp so that it...Ch. 35 - An object is placed 10.0 cm from a diverging lens...Ch. 35 - In Figure P35.30, a thin converging lens of focal...Ch. 35 - You are working for an electronics company that...Ch. 35 - Prob. 32PCh. 35 - Two rays traveling parallel to the principal axis...Ch. 35 - Josh cannot see objects clearly beyond 25.0 cm...Ch. 35 - Figure 35.34 diagrams a cross section of a camera....Ch. 35 - The refracting telescope at the Yerkes Observatory...Ch. 35 - The distance between the eyepiece and the...Ch. 35 - What are (a) the maximum angular magnification...Ch. 35 - A patient has a near point of 45.0 cm and far...Ch. 35 - The intensity I of the light reaching the CCD in a...Ch. 35 - A certain childs near point is 10.0 cm; her far...Ch. 35 - Astronomers often take photographs with the...Ch. 35 - A simple model of the human eye ignores its lens...Ch. 35 - A real object is located at the zero end of a...Ch. 35 - The distance between an object and its upright...Ch. 35 - Prob. 46APCh. 35 - Andy decides to use an old pair of eyeglasses to...Ch. 35 - Two converging lenses having focal lengths of f1 =...Ch. 35 - Two lenses made of kinds of glass having different...Ch. 35 - Prob. 50APCh. 35 - An object is placed 12.0 cm to the left of a...Ch. 35 - An object is placed a distance p to the left of a...Ch. 35 - In a darkened room, a burning candle is placed...Ch. 35 - In many applications, it is necessary to expand or...Ch. 35 - Why is the following situation impossible?...Ch. 35 - A zoom lens system is a combination of lenses that...Ch. 35 - Consider the lensmirror arrangement shown in...Ch. 35 - A floating strawberry illusion is achieved with...
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- A coat hanger of mass m = 0.255 kg oscillates on a peg as a physical pendulum as shown in the figure below. The distance from the pivot to the center of mass of the coat hanger is d = 18.0 cm and the period of the motion is T = 1.37 s. Find the moment of inertia of the coat hanger about the pivot.arrow_forwardReview Conceptual Example 3 and the drawing as an aid in solving this problem. A conducting rod slides down between two frictionless vertical copper tracks at a constant speed of 3.9 m/s perpendicular to a 0.49-T magnetic field. The resistance of th rod and tracks is negligible. The rod maintains electrical contact with the tracks at all times and has a length of 1.4 m. A 1.1-Q resistor is attached between the tops of the tracks. (a) What is the mass of the rod? (b) Find the change in the gravitational potentia energy that occurs in a time of 0.26 s. (c) Find the electrical energy dissipated in the resistor in 0.26 s.arrow_forwardA camera lens used for taking close-up photographs has a focal length of 21.5 mm. The farthest it can be placed from the film is 34.0 mm. (a) What is the closest object (in mm) that can be photographed? 58.5 mm (b) What is the magnification of this closest object? 0.581 × ×arrow_forward
- Given two particles with Q = 4.40-µC charges as shown in the figure below and a particle with charge q = 1.40 ✕ 10−18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) Three positively charged particles lie along the x-axis of the x y coordinate plane.Charge q is at the origin.Charge Q is at (0.800 m, 0).Another charge Q is at (−0.800 m, 0).(a)What is the net force (in N) exerted by the two 4.40-µC charges on the charge q? (Enter the magnitude.) N(b)What is the electric field (in N/C) at the origin due to the two 4.40-µC particles? (Enter the magnitude.) N/C(c)What is the electrical potential (in kV) at the origin due to the two 4.40-µC particles? kV(d)What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 4.40-µC particles?arrow_forward(a) Where does an object need to be placed relative to a microscope in cm from the objective lens for its 0.500 cm focal length objective to produce a magnification of -25? (Give your answer to at least three decimal places.) 0.42 × cm (b) Where should the 5.00 cm focal length eyepiece be placed in cm behind the objective lens to produce a further fourfold (4.00) magnification? 15 × cmarrow_forwardIn a LASIK vision correction, the power of a patient's eye is increased by 3.10 D. Assuming this produces normal close vision, what was the patient's near point in m before the procedure? (The power for normal close vision is 54.0 D, and the lens-to-retina distance is 2.00 cm.) 0.98 x marrow_forward
- Don't use ai to answer I will report you answerarrow_forwardA shopper standing 2.00 m from a convex security mirror sees his image with a magnification of 0.200. (Explicitly show on paper how you follow the steps in the Problem-Solving Strategy for mirrors found on page 1020. Your instructor may ask you to turn in this work.) (a) Where is his image (in m)? (Use the correct sign.) -0.4 m in front of the mirror ▾ (b) What is the focal length (in m) of the mirror? -0.5 m (c) What is its radius of curvature (in m)? -1.0 marrow_forwardAn amoeba is 0.309 cm away from the 0.304 cm focal length objective lens of a microscope.arrow_forward
- Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are connected in series, the current is Is. When the resistors are connected in parallel, the current Ip from the source is equal to 10Is. Let r be the ratio R1/R2. Find r. I know you have to find the equations for V for both situations and relate them, I'm just struggling to do so. Please explain all steps, thank you.arrow_forwardBheem and Ram, jump off either side of a bridge while holding opposite ends of a rope and swing back and forth under the bridge to save a child while avoiding a fire. Looking at the swing of just Bheem, we can approximate him as a simple pendulum with a period of motion of 5.59 s. How long is the pendulum ? When Bheem swings, he goes a full distance, from side to side, of 10.2 m. What is his maximum velocity? What is his maximum acceleration?arrow_forwardThe position of a 0.300 kg object attached to a spring is described by x=0.271 m ⋅ cos(0.512π⋅rad/s ⋅t) (Assume t is in seconds.) Find the amplitude of the motion. Find the spring constant. Find the position of the object at t = 0.324 s. Find the object's velocity at t = 0.324 s.arrow_forward
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