Physics for Scientists and Engineers
10th Edition
ISBN: 9781337553278
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
thumb_up100%
Chapter 35, Problem 48AP
Two converging lenses having focal lengths of f1 = 10.0 cm and f2 = 20.0 cm are placed a distance d = 50.0 cm apart as shown in Figure P35.48. The image due to light passing through both lenses is to be located between the lenses at the position x = 31.0 cm indicated. (a) At what value of p should the object be positioned to the left of the first lens? (b) What is the magnification of the final image? (c) Is the final image upright or inverted? (d) Is the final image real or virtual?
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Consider the situation in the figure below; a neutral conducting ball hangs from the ceiling by an insulating string, and a charged insulating rod is going to be placed nearby.
A. First, if the rod was not there, what statement best describes the charge distribution of the ball?
1) Since it is a conductor, all the charges are on the outside of the ball. 2) The ball is neutral, so it has no positive or negative charges anywhere. 3) The positive and negative charges are separated from each other, but we don't know what direction the ball is polarized. 4) The positive and negative charges are evenly distributed everywhere in the ball.
B. Now, when the rod is moved close to the ball, what happens to the charges on the ball?
1) There is a separation of charges in the ball; the side closer to the rod becomes positively charged, and the opposite side becomes negatively charged. 2) Negative charge is drawn from the ground (via the string), so the ball acquires a net negative charge. 3)…
answer question 5-9
AMPS
VOLTS
OHMS
5) 50 A
110 V
6) .08 A
39 V
7) 0.5 A
60
8) 2.5 A
110 V
Chapter 35 Solutions
Physics for Scientists and Engineers
Ch. 35.1 - You are standing approximately 2 m away from a...Ch. 35.2 - You wish to start a fire by reflecting sunlight...Ch. 35.2 - Consider the image in the mirror in Figure 35.14....Ch. 35.3 - Prob. 35.4QQCh. 35.3 - Prob. 35.5QQCh. 35.4 - What is the focal length of a pane of window...Ch. 35.6 - Two campers wish to start a fire during the day....Ch. 35 - (a) Does your bathroom mirror show you older or...Ch. 35 - Two flat mirrors have their reflecting surfaces...Ch. 35 - A periscope (Fig. P35.3) is useful for viewing...
Ch. 35 - Two plane mirrors stand facing each other, 3.00 m...Ch. 35 - An object is placed 50.0 cm from a concave...Ch. 35 - An object is placed 20.0 cm from a concave...Ch. 35 - An object of height 2.00 cm is placed 30.0 cm from...Ch. 35 - Why is the following situation impossible? At a...Ch. 35 - A large hall in a museum has a niche in one wall....Ch. 35 - A concave spherical mirror has a radius of...Ch. 35 - An object 10.0 cm tall is placed at the zero mark...Ch. 35 - You are training to become an opticians assistant....Ch. 35 - A certain Christmas tree ornament is a silver...Ch. 35 - Review. A ball is dropped at t = 0 from rest 3.00...Ch. 35 - You unconsciously estimate the distance to an...Ch. 35 - A convex spherical mirror has a focal length of...Ch. 35 - One end of a long glass rod (n = 1.50) is formed...Ch. 35 - Prob. 18PCh. 35 - Prob. 19PCh. 35 - Figure P35.20 (page 958) shows a curved surface...Ch. 35 - To dress up your dorm room, you have purchased a...Ch. 35 - You are working for a solar energy company. Your...Ch. 35 - An object located 32.0 cm in front of a lens forms...Ch. 35 - An objects distance from a converging lens is 5.00...Ch. 35 - A contact lens is made of plastic with an index of...Ch. 35 - A converging lens has a focal length of 10.0 cm....Ch. 35 - A converging lens has a focal length of 10.0 cm....Ch. 35 - Suppose an object has thickness dp so that it...Ch. 35 - An object is placed 10.0 cm from a diverging lens...Ch. 35 - In Figure P35.30, a thin converging lens of focal...Ch. 35 - You are working for an electronics company that...Ch. 35 - Prob. 32PCh. 35 - Two rays traveling parallel to the principal axis...Ch. 35 - Josh cannot see objects clearly beyond 25.0 cm...Ch. 35 - Figure 35.34 diagrams a cross section of a camera....Ch. 35 - The refracting telescope at the Yerkes Observatory...Ch. 35 - The distance between the eyepiece and the...Ch. 35 - What are (a) the maximum angular magnification...Ch. 35 - A patient has a near point of 45.0 cm and far...Ch. 35 - The intensity I of the light reaching the CCD in a...Ch. 35 - A certain childs near point is 10.0 cm; her far...Ch. 35 - Astronomers often take photographs with the...Ch. 35 - A simple model of the human eye ignores its lens...Ch. 35 - A real object is located at the zero end of a...Ch. 35 - The distance between an object and its upright...Ch. 35 - Prob. 46APCh. 35 - Andy decides to use an old pair of eyeglasses to...Ch. 35 - Two converging lenses having focal lengths of f1 =...Ch. 35 - Two lenses made of kinds of glass having different...Ch. 35 - Prob. 50APCh. 35 - An object is placed 12.0 cm to the left of a...Ch. 35 - An object is placed a distance p to the left of a...Ch. 35 - In a darkened room, a burning candle is placed...Ch. 35 - In many applications, it is necessary to expand or...Ch. 35 - Why is the following situation impossible?...Ch. 35 - A zoom lens system is a combination of lenses that...Ch. 35 - Consider the lensmirror arrangement shown in...Ch. 35 - A floating strawberry illusion is achieved with...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The drawing shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m², while surface (2) has an area of 3.90 m². The electric field in the drawing is uniform and has a magnitude of 215 N/C. Find the magnitude of the electric flux through surface (1 and 2 combined) if the angle 8 made between the electric field with surface (2) is 30.0°. Solve in Nm²/C 1 Ө Surface 2 Surface 1arrow_forwardPROBLEM 5 What is the magnitude and direction of the resultant force acting on the connection support shown here? F₁ = 700 lbs F2 = 250 lbs 70° 60° F3 = 700 lbs 45° F4 = 300 lbs 40° Fs = 800 lbs 18° Free Body Diagram F₁ = 700 lbs 70° 250 lbs 60° F3= = 700 lbs 45° F₁ = 300 lbs 40° = Fs 800 lbs 18°arrow_forwardPROBLEM 3 Cables A and B are Supporting a 185-lb wooden crate. What is the magnitude of the tension force in each cable? A 20° 35° 185 lbsarrow_forward
- The determined Wile E. Coyote is out once more to try to capture the elusive Road Runner of Loony Tunes fame. The coyote is strapped to a rocket, which provide a constant horizontal acceleration of 15.0 m/s2. The coyote starts off at rest 79.2 m from the edge of a cliff at the instant the roadrunner zips by in the direction of the cliff. If the roadrunner moves with constant speed, find the minimum velocity the roadrunner must have to reach the cliff before the coyote. (proper sig fig in answer)arrow_forwardPROBLEM 4 What is the resultant of the force system acting on the connection shown? 25 F₁ = 80 lbs IK 65° F2 = 60 lbsarrow_forwardThree point-like charges in the attached image are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 38.0 cm, and the point (C) is located half way between q1 and q3 along the side. Find the magnitude of the electric field at point (C). Let q1 = −2.80 µC, q2 = −3.40 µC, and q3 = −4.50 µC. Thank you.arrow_forward
- STRUCTURES I Homework #1: Force Systems Name: TA: PROBLEM 1 Determine the horizontal and vertical components of the force in the cable shown. PROBLEM 2 The horizontal component of force F is 30 lb. What is the magnitude of force F? 6 10 4 4 F = 600lbs F = ?arrow_forwardThe determined Wile E. Coyote is out once more to try to capture the elusive Road Runner of Loony Tunes fame. The coyote is strapped to a rocket, which provide a constant horizontal acceleration of 15.0 m/s2. The coyote starts off at rest 79.2 m from the edge of a cliff at the instant the roadrunner zips by in the direction of the cliff. If the roadrunner moves with constant speed, find the minimum velocity the roadrunner must have to reach the cliff before the coyote. (proper sig fig)arrow_forwardHello, I need some help with calculations for a lab, it is Kinematics: Finding Acceleration Due to Gravity. Equations: s=s0+v0t+1/2at2 and a=gsinθ. The hypotenuse,r, is 100cm (given) and a height, y, is 3.5 cm (given). How do I find the Angle θ1? And, for distance traveled, s, would all be 100cm? For my first observations I recorded four trials in seconds: 1 - 2.13s, 2 - 2.60s, 3 - 2.08s, & 4 - 1.95s. This would all go in the coloumn for time right? How do I solve for the experimental approximation of the acceleration? Help with trial 1 would be great so I can use that as a model for the other trials. Thanks!arrow_forward
- After the countdown at the beginning of a Mario Kart race, Bowser slams on the gas, taking off from rest. Bowser get up to a full speed of 25.5 m/s due to an acceleration of 10.4 m/s2. A)How much time does it take to reach full speed? B) How far does Bowser travel while accelerating?arrow_forwardThe drawing in the image attached shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Side 1 has an area of 1.90 m^2, Side 2 has an area of 3.90 m^2, the electric field in magnitude is around 215 N/C. Please find the electric flux magnitude through side 1 and 2 combined if the angle (theta) made between the electric field with side 2 is 30.0 degrees. I believe side 1 is 60 degrees but could be wrong. Thank you.arrow_forwardAfter the countdown at the beginning of a Mario Kart race, Bowser slams on the gas, taking off from rest. Bowser get up to a full speed of 25.5 m/s due to an acceleration of 10.4 m/s2.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY