Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3.4, Problem 41STP
To determine

To calculate: The system of equations that represent the number of hats and shirts bought each year.

Expert Solution & Answer
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Answer to Problem 41STP

The system of equations is {7x+15y=3308x+16y=360 . The number hats are 15 and shirts are also 15.

Explanation of Solution

Given information:

The cost of 1 hat was $7 and one shirt was $15 so the chess team paid $330 last year. Now, they paid $360 and cost of 1 hat is $8 and cost of 1 shirt is $16.

Calculation:

Consider the provided information that cost of 1 hat was $7 and one shirt was $15 so the chess team paid $330 last year. Now, they paid $360 and cost of 1 hat is $8 and cost of 1 shirt is $16.

Let x denote the number of hats and y denote the number of shirts.

Consider the system of equations that represent the situation above.

  7x+15y=3308x+16y=360

Use the method of substitution to solve the system above.

From the equation 7x+15y=330 isolate the value of y ,

  7x+15y=330y=3307x15

Now substitute y=3307x15 in the equation 8x+16y=360 ,

  8x+16(3307x15)=360120x+5280112x=5400x=15

Now, substitute x=15 in the equation y=3307x15 ,

  y=3307(15)15y=15

Therefore, solution is the coordinate pair, (15,15).

Thus, the system of equations is {7x+15y=3308x+16y=360 . The number hats are 15 and shirts are also 15.

Chapter 3 Solutions

Algebra 2

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42HPCh. 3.1 - Prob. 43HPCh. 3.1 - Prob. 44HPCh. 3.1 - Prob. 45HPCh. 3.1 - Prob. 46HPCh. 3.1 - Prob. 47HPCh. 3.1 - Prob. 48HPCh. 3.1 - Prob. 49HPCh. 3.1 - 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