Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3, Problem 21MCQ
To determine

To explain: The system of equations that can be used to find the price of paint and primer.

  F.    p=r+12rp+2r=42

  G.    r=p+12pp+2p=42

  H.    p=r+2rp+12r=42

  I.     r=p+2pp+12=42

Expert Solution & Answer
Check Mark

Answer to Problem 21MCQ

The system of equations that can be used to find number of tickets sold on each day is ft=56f+t=406 . Option F. is correct.

Explanation of Solution

Given information:

Tia spent $42 on 2 cans of primer and 1 can of paint for her room. The price of paint p is 150% of the price of primer r .

Formula used:

To frame system of equations, convert the language of word problem to mathematical statements by assuming the values of unknown as variables.

Calculation:

Consider the provided information that Tia spent $42 on 2 cans of primer and 1 can of paint for her room. The price of paint p is 150% of the price of primer r .

Recall that to frame system of equations, convert the language of word problem to mathematical statements by assuming the values of unknown as variables.

The price of a can of paint is p and price of a can of primer is r .

Then according to the statement that “The price of paint p is 150% of the price of primer r ”, the mathematical statement in terms of variable will be,

  p=150% of rp=150100rp=32rp=r+12r

Now, according to statement that “Tia spent $42 on 2 cans of primer and 1 can of paint for her room”, the equation so formed will be,

  2r+p=42

Therefore, the system of equation is,

  p=r+12rp+2r=42

Thus, the system of equations that can be used to find number of tickets sold on each day is

  p=r+12rp+2r=42 .

Option F. is correct.

Chapter 3 Solutions

Algebra 2

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42HPCh. 3.1 - Prob. 43HPCh. 3.1 - Prob. 44HPCh. 3.1 - Prob. 45HPCh. 3.1 - Prob. 46HPCh. 3.1 - Prob. 47HPCh. 3.1 - Prob. 48HPCh. 3.1 - Prob. 49HPCh. 3.1 - 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