Answer Problems 83 and 84 using the following: A quadratic function of the form f ( x ) = a x 2 + b x + c with b 2 − 4 a c > 0 may also be written in the form f ( x ) = a ( x – r 1 ) ( x − r 2 ) , where r 1 and r 2 are the x -intercepts of the graph of the quadratic function. (a) Find a quadratic function whose x -intercepts are − 5 and 3 with a = 1 ; a = 2 ; a = − 2 ; a = 5 . (b) How does the value of a affect the intercepts? (c) How does the value of a affect the axis of symmetry? (d) How does the value of a affect the vertex? (e) Compare the x -coordinate of the vertex with the midpoint of the x -intercepts . What might you conclude?
Answer Problems 83 and 84 using the following: A quadratic function of the form f ( x ) = a x 2 + b x + c with b 2 − 4 a c > 0 may also be written in the form f ( x ) = a ( x – r 1 ) ( x − r 2 ) , where r 1 and r 2 are the x -intercepts of the graph of the quadratic function. (a) Find a quadratic function whose x -intercepts are − 5 and 3 with a = 1 ; a = 2 ; a = − 2 ; a = 5 . (b) How does the value of a affect the intercepts? (c) How does the value of a affect the axis of symmetry? (d) How does the value of a affect the vertex? (e) Compare the x -coordinate of the vertex with the midpoint of the x -intercepts . What might you conclude?
Solution Summary: The author explains that the x-coordinate of the vertex and axis of symmetry are all the same.
Answer Problems 83 and 84 using the following: A quadratic function of the form
with
may also be written in the form
, where
are the
of the graph of the quadratic function.
(a) Find a quadratic function whose
are
and 3 with
.
(b) How does the value of
affect the intercepts?
(c) How does the value of
affect the axis of symmetry?
(d) How does the value of
affect the vertex?
(e) Compare the
of the vertex with the midpoint of the
. What might you conclude?
Good Day,
Would appreciate any assistance with this query.
Regards,
This question builds on an earlier problem. The randomized numbers may have changed, but have your work for the previous problem available to help with this one.
A 4-centimeter rod is attached at one end to a point A rotating counterclockwise on a wheel of radius 2 cm. The other end B is free to move back and forth along a horizontal bar that goes through the center of the wheel. At time t=0 the rod is situated as in the diagram at the left below. The
wheel rotates counterclockwise at 1.5 rev/sec. At some point, the rod will be tangent to the circle as shown in the third picture.
A
B
A
B
at some instant, the piston will be tangent to the circle
(a) Express the x and y coordinates of point A as functions of t:
x= 2 cos(3πt)
and y= 2 sin(3t)
(b) Write a formula for the slope of the tangent line to the circle at the point A at time t seconds:
-cot(3πt)
sin(3лt)
(c) Express the x-coordinate of the right end of the rod at point B as a function of t: 2 cos(3πt) +411-
4
-2 sin (3лt)
(d)…
5. [-/1 Points]
DETAILS
MY NOTES
SESSCALCET2 6.5.AE.003.
y
y= ex²
0
Video Example
x
EXAMPLE 3
(a) Use the Midpoint Rule with n = 10 to approximate the integral
कर
L'ex²
dx.
(b) Give an upper bound for the error involved in this approximation.
SOLUTION
8+2
1
L'ex² d
(a) Since a = 0, b = 1, and n = 10, the Midpoint Rule gives the following. (Round your answer to six decimal places.)
dx Ax[f(0.05) + f(0.15) + ... + f(0.85) + f(0.95)]
0.1 [0.0025 +0.0225
+
+ e0.0625 + 0.1225
e0.3025 + e0.4225
+ e0.2025
+
+ e0.5625 €0.7225 +0.9025]
The figure illustrates this approximation.
(b) Since f(x) = ex², we have f'(x)
=
0 ≤ f'(x) =
< 6e.
ASK YOUR TEACHER
and f'(x) =
Also, since 0 ≤ x ≤ 1 we have x² ≤
and so
Taking K = 6e, a = 0, b = 1, and n = 10 in the error estimate, we see that an upper bound for the error is as follows. (Round your final
answer to five decimal places.)
6e(1)3
e
24(
=
≈
Chapter 3 Solutions
Precalculus Enhanced with Graphing Utilities, Books a la Carte Edition Plus NEW MyLab Math -- Access Card Package (7th Edition)
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Differential Equation | MIT 18.01SC Single Variable Calculus, Fall 2010; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=HaOHUfymsuk;License: Standard YouTube License, CC-BY