Chapter 3, Problem 76QAP

Acetic acid (HC₂H₃O₂) can be prepared by the action of the acetobacter organism on dilute solutions of ethanol (C₂H₅OH). The equation for the reaction is

${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH}\left(aq\right)+{\text{O}}_{\text{2}}\left(g\right)\to {\text{HC}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\left(aq\right)+{\text{H}}_{\text{2}}\text{O}$How many milliliters of a 12.5% (by volume) solution of ethanol are required to produce 175 mL of 0.664 M acetic acid? $\left(\text{Density of pure ethanol}=0.\text{789 g}/\text{mL}.\right)$