(a) Interpretation: The number of moles of platinum in the cone should be calculated. Concept introduction: The number of moles of a substance is related to molar mass of the substance as follows: n = m M Here, m is mass and M is molar mass. In 1 mol of a substance there are 6.023 × 10 23 units of that substance. Also, density of a substance is related to mass and volume as follows: d = m V Here, m is mass and V is volume of the substance.
(a) Interpretation: The number of moles of platinum in the cone should be calculated. Concept introduction: The number of moles of a substance is related to molar mass of the substance as follows: n = m M Here, m is mass and M is molar mass. In 1 mol of a substance there are 6.023 × 10 23 units of that substance. Also, density of a substance is related to mass and volume as follows: d = m V Here, m is mass and V is volume of the substance.
Definition Definition Number of atoms/molecules present in one mole of any substance. Avogadro's number is a constant. Its value is 6.02214076 × 10 23 per mole.
Chapter 3, Problem 6QAP
Interpretation Introduction
(a)
Interpretation:
The number of moles of platinum in the cone should be calculated.
Concept introduction:
The number of moles of a substance is related to molar mass of the substance as follows:
n=mM
Here, m is mass and M is molar mass.
In 1 mol of a substance there are 6.023×1023 units of that substance.
Also, density of a substance is related to mass and volume as follows:
d=mV
Here, m is mass and V is volume of the substance.
Interpretation Introduction
(b)
Interpretation:
The number of electrons in there in the cone should be calculated.
Concept introduction:
The number of moles of a substance is related to molar mass of the substance as follows:
n=mM
Here, m is mass and M is molar mass.
According to Avogadro’s law, in 1 mol of a substance there are 6.023×1023 units of that substance.
Condensation polymers are produced when monomers containing two different functional groups link together with the loss of a small molecule such as H2O.
The difunctional monomer H2N(CH2)6COOH forms a condensation polymer. Draw the carbon-skeleton structure of the dimer that forms from this monomer.
What is the structure of the monomer?
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AP Biology Notes
Gamino acid chart - G...
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=HA O=A¯ = H₂O
Acid
HIO
HBrO
HCIO
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