Asymmetric method of sealed bids . Suppose that an estate consisting of M indivisible items is to be divided among N heirs ( P 1 , P 2 , ... , P N ) using the method of sealed bids. Suppose that Grandma’s will stipulates that P 1 is entitled to x 1 % of the estate, P 2 is entitled to x 2 % of the estate,…, P N is entitled to x N % of the estate. The percentages add up to 100%, but they are not all equal (Grandma loved some grandchildren more than others). Describe a variation of the method of sealed bids that ensures that each player receives a “fair share” (i.e., P 1 receives a share that she considers to be worth at least x 1 % of the estate, P 2 receives a share that he considers to be worth at least x 2 % of the estate, etc.).
Asymmetric method of sealed bids . Suppose that an estate consisting of M indivisible items is to be divided among N heirs ( P 1 , P 2 , ... , P N ) using the method of sealed bids. Suppose that Grandma’s will stipulates that P 1 is entitled to x 1 % of the estate, P 2 is entitled to x 2 % of the estate,…, P N is entitled to x N % of the estate. The percentages add up to 100%, but they are not all equal (Grandma loved some grandchildren more than others). Describe a variation of the method of sealed bids that ensures that each player receives a “fair share” (i.e., P 1 receives a share that she considers to be worth at least x 1 % of the estate, P 2 receives a share that he considers to be worth at least x 2 % of the estate, etc.).
Solution Summary: The author explains the method of sealed bids, which ensures that each player receives a fair share of the estate.
Asymmetric method of sealed bids. Suppose that an estate consisting of M indivisible items is to be divided among N heirs
(
P
1
,
P
2
,
...
,
P
N
)
using the method of sealed bids. Suppose that Grandma’s will stipulates that
P
1
is entitled to
x
1
%
of the estate,
P
2
is entitled to
x
2
%
of the estate,…,
P
N
is entitled to
x
N
%
of the estate. The percentages add up to 100%, but they are not all equal (Grandma loved some grandchildren more than others). Describe a variation of the method of sealed bids that ensures that each player receives a “fair share” (i.e.,
P
1
receives a share that she considers to be worth at least
x
1
%
of the estate,
P
2
receives a share that he considers to be worth at least
x
2
%
of the estate, etc.).
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.