Direction: Strictly write in 4 bond paper, because my activity book have 4 spaces. This is actually for maritime industry course, but I think geometry can do this. Use nautical almanac. Sample calculation: Clatitude by meridian altitude - Sun) On 4th April 1988, In DR position 35°10'N 148° 18°E, the sextant meridian altitude of the sun's lower limb was 60° 10.3. If IE was 2.2' off. the arc. and He was 12 meters, find the latitude and the position line. Sext alt: IE (off) 60° 10.3' (+) 02.2 Obs alt: 60°12.5' Dip (12m): (-) 06.1 App alt: 60.06.4' Tot com LL (1) 15.4' I alt: 60021.8'5 M2D: 29°32.2'N LMT Mer Pass: 04d 12h 03m 00s LIT(E): (-) 09h 53m 12s GMT Mer Pass: Dec (o4d 02 h): 09d 02h 09m 48c 05° 33.8'N (0.9): (+) 00.1 Dec 05° 334°N MZD: 29° 38.2'N Lat 35° 12.1'N PL E-W if similar MZD and Dec are same name-add and retain name. If they are opposite names subtract the smaller one from the larger one and retain the name of larger one.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter6: Ratio, Proportion, And Probability
Section6.5: Similarity And Measurement
Problem 2E
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I have ai  answers but incorrect 

Direction: Strictly write in 4 bond paper, because my activity book have
4 spaces. This is actually for maritime industry course, but I
think geometry can do this. Use nautical almanac.
Sample calculation: Clatitude by meridian altitude - Sun)
On 4th April 1988, In DR position 35°10'N 148° 18°E, the sextant meridian
altitude of the sun's lower limb was 60° 10.3. If IE was 2.2' off.
the arc. and He was 12 meters, find the latitude and the position line.
Sext alt:
IE (off)
60° 10.3'
(+)
02.2
Obs alt:
60°12.5'
Dip (12m):
(-)
06.1
App alt:
60.06.4'
Tot com LL
(1)
15.4'
I alt:
60021.8'5
M2D:
29°32.2'N
LMT Mer Pass:
04d 12h 03m 00s
LIT(E):
(-)
09h 53m 12s
GMT Mer Pass:
Dec (o4d 02 h):
09d 02h 09m 48c
05° 33.8'N
(0.9):
(+)
00.1
Dec
05° 334°N
MZD:
29° 38.2'N
Lat
35° 12.1'N
PL E-W
if similar MZD and Dec are same name-add and retain name. If they
are opposite names subtract the smaller one from the larger one and
retain the name of larger one.
Transcribed Image Text:Direction: Strictly write in 4 bond paper, because my activity book have 4 spaces. This is actually for maritime industry course, but I think geometry can do this. Use nautical almanac. Sample calculation: Clatitude by meridian altitude - Sun) On 4th April 1988, In DR position 35°10'N 148° 18°E, the sextant meridian altitude of the sun's lower limb was 60° 10.3. If IE was 2.2' off. the arc. and He was 12 meters, find the latitude and the position line. Sext alt: IE (off) 60° 10.3' (+) 02.2 Obs alt: 60°12.5' Dip (12m): (-) 06.1 App alt: 60.06.4' Tot com LL (1) 15.4' I alt: 60021.8'5 M2D: 29°32.2'N LMT Mer Pass: 04d 12h 03m 00s LIT(E): (-) 09h 53m 12s GMT Mer Pass: Dec (o4d 02 h): 09d 02h 09m 48c 05° 33.8'N (0.9): (+) 00.1 Dec 05° 334°N MZD: 29° 38.2'N Lat 35° 12.1'N PL E-W if similar MZD and Dec are same name-add and retain name. If they are opposite names subtract the smaller one from the larger one and retain the name of larger one.
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