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using this model estimate the weight of a person who is 167 cm tall and whose BSA is 2.2
BSA=sqrt(w*h/3600)
where w is weight and h is height
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Solved in 2 steps
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- Analytically consider the variation of rainfall around a typical rain gauge that registered 2.0 mm of rainfall. Accurately estimate the depth (mm) of rainfall at a spot that is 50 m away from the rain gauge. (a) 2.0 (b) > 2.0 (c) < 2.0 (d) (e) 0.5Sand falls from a conveyor belt at the rate of 10 m3/min onto the top of a conical pile. The height of the pile is always three-eighths of the base diameter. How fast are the (a) height and (b) radius changing when the pile is 4 m high? Answer in centimeters per minute.A 30-second commercial during Super Bowl XXXVII in 2003 cost advertisers 2.2 million. For the first Super Bowl in 1967, an advertiser could have purchased approximately 26.19 minutes of advertising time for the same amount of money. (a) Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 2003 Super Bowl. cost= dollars/second. (round to nearest cent and do not enter commas) (b) Assuming that advertising cost is proportional to its length of time, find the cost of advertising, in dollars/second, during the 1967 Super Bowl. cost = dollars/second. (round to nearest cent and do not enter commas) (c) How many times more expensive was Super Bowl advertising in 2003 than in 1967? times more expensive (round to nearest whole number)
