Suppose that N players bid on M items using the method of sealed bids. Let T denote the table with M rows (one for each item) and N columns (one for each player) containing all the players' bids (i.e., the entry in column j , row k represents player j 's bid for item k ). Let c 1 , c 2 , … , c N denote, respectively, the sum of the entries in column 1, column 2,…, column N of T , and let r 1 , r 2 , … , r M denote, respectively, the sum of the entries in row 1, row 2,…, row M of T . Let w 1 , w 2 , … , w M denote the winning bids for items 1 , 2 , … , M , respectively (i.e., w 1 is the largest entry in row 1 of T , w 2 is the largest entry in row 2, etc.). Let S denote the surplus money left after the first settlement. a. Show that S = ( w 1 + w 2 + ⋯ + w M ) − ( c 1 + c 2 + ⋯ + c N ) / N . b. Using (a), show that S = ( w 1 − r 1 N ) + ( w 2 − r 2 N ) + ⋯ + ( w M − r M N ) . c. Using (b), show that S ≥ 0 . d. Describe the conditions under which S = 0
Suppose that N players bid on M items using the method of sealed bids. Let T denote the table with M rows (one for each item) and N columns (one for each player) containing all the players' bids (i.e., the entry in column j , row k represents player j 's bid for item k ). Let c 1 , c 2 , … , c N denote, respectively, the sum of the entries in column 1, column 2,…, column N of T , and let r 1 , r 2 , … , r M denote, respectively, the sum of the entries in row 1, row 2,…, row M of T . Let w 1 , w 2 , … , w M denote the winning bids for items 1 , 2 , … , M , respectively (i.e., w 1 is the largest entry in row 1 of T , w 2 is the largest entry in row 2, etc.). Let S denote the surplus money left after the first settlement. a. Show that S = ( w 1 + w 2 + ⋯ + w M ) − ( c 1 + c 2 + ⋯ + c N ) / N . b. Using (a), show that S = ( w 1 − r 1 N ) + ( w 2 − r 2 N ) + ⋯ + ( w M − r M N ) . c. Using (b), show that S ≥ 0 . d. Describe the conditions under which S = 0
Solution Summary: The author explains the method of sealed bids. Each player makes a bid for each of the items in the estate.
Suppose that N players bid on M items using the method of sealed bids. Let T denote the table with M rows (one for each item) and N columns (one for each player) containing all the players' bids (i.e., the entry in column j, row k represents player j's bid for item k). Let
c
1
,
c
2
,
…
,
c
N
denote, respectively, the sum of the entries in column 1, column 2,…, column N of T, and let
r
1
,
r
2
,
…
,
r
M
denote, respectively, the sum of the entries in row 1, row 2,…, row M of T. Let
w
1
,
w
2
,
…
,
w
M
denote the winning bids for items
1
,
2
,
…
,
M
, respectively (i.e.,
w
1
is the largest entry in row 1 of T,
w
2
is the largest entry in row 2, etc.). Let S denote the surplus money left after the first settlement.
a. Show that
S
=
(
w
1
+
w
2
+
⋯
+
w
M
)
−
(
c
1
+
c
2
+
⋯
+
c
N
)
/
N
.
b. Using (a), show that
S
=
(
w
1
−
r
1
N
)
+
(
w
2
−
r
2
N
)
+
⋯
+
(
w
M
−
r
M
N
)
.
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.