Suppose that Angelina values strawberry cake five as much as she values chocolate cake. Find the dollar value to Angelina of each of the following pieces: a. the strawberry wedge shown in Fig . 3 − 17 ( a ) _ b. the chocolate slice shown in Fig . 3 − 17 ( b ) _ c. the strawberry sliver shown in Fig . 3 − 17 ( c ) _
Suppose that Angelina values strawberry cake five as much as she values chocolate cake. Find the dollar value to Angelina of each of the following pieces: a. the strawberry wedge shown in Fig . 3 − 17 ( a ) _ b. the chocolate slice shown in Fig . 3 − 17 ( b ) _ c. the strawberry sliver shown in Fig . 3 − 17 ( c ) _
Solution Summary: The author analyzes how the dollar value to Angelina of strawberry wedge is 20.
Suppose that Angelina values strawberry cake five as much as she values chocolate cake. Find the dollar value to Angelina of each of the following pieces:
a. the strawberry wedge shown in
Fig
.
3
−
17
(
a
)
_
b. the chocolate slice shown in
Fig
.
3
−
17
(
b
)
_
c. the strawberry sliver shown in
Fig
.
3
−
17
(
c
)
_
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
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