Exercise 35 through 38 refer to the following situation: Angela, Boris, and Carlos are dividing the vanilla-strawberry cake shown in Fig.3-23(a) using the lone-chooser method. Fig.3-23(b) shows how each player values each half of the cake. In your answers assume that all cuts are normal “cake cuts” from the center to the edge of the cake. You can describe each piece of cake by giving the angles of the vanilla and strawberry parts, as in “ 15 ° strawberry- 40 ° vanilla” or “ 60 ° vanilla only.” Suppose that Carlos and Angela are the dividers and Boris is the chooser. In the first division, Carlos cuts the cake vertically through the center as shown in Fig.3-24, with Angela choosing s 1 (the left half) and Carlos s 2 (the right half). In the second division, Angela subdivides s 2 into three pieces. a. Describe how Carlos would subdivide s 2 into three pieces. b. Describe how Angela would subdivide s 1 into three pieces. c. Based on the subdivisions in (a) and (b), describe a possible final fair division of the cake. d. For the final fair division you described in (c), find the value (in dollars and cents) of each share in the eyes of the player receiving it.
Exercise 35 through 38 refer to the following situation: Angela, Boris, and Carlos are dividing the vanilla-strawberry cake shown in Fig.3-23(a) using the lone-chooser method. Fig.3-23(b) shows how each player values each half of the cake. In your answers assume that all cuts are normal “cake cuts” from the center to the edge of the cake. You can describe each piece of cake by giving the angles of the vanilla and strawberry parts, as in “ 15 ° strawberry- 40 ° vanilla” or “ 60 ° vanilla only.” Suppose that Carlos and Angela are the dividers and Boris is the chooser. In the first division, Carlos cuts the cake vertically through the center as shown in Fig.3-24, with Angela choosing s 1 (the left half) and Carlos s 2 (the right half). In the second division, Angela subdivides s 2 into three pieces. a. Describe how Carlos would subdivide s 2 into three pieces. b. Describe how Angela would subdivide s 1 into three pieces. c. Based on the subdivisions in (a) and (b), describe a possible final fair division of the cake. d. For the final fair division you described in (c), find the value (in dollars and cents) of each share in the eyes of the player receiving it.
Solution Summary: The author explains how Carlos would subdivide s_2 into three pieces using lone chooser method.
Exercise 35 through 38 refer to the following situation: Angela, Boris, and Carlos are dividing the vanilla-strawberry cake shown in Fig.3-23(a) using the lone-chooser method. Fig.3-23(b) shows how each player values each half of the cake. In your answers assume that all cuts are normal “cake cuts” from the center to the edge of the cake. You can describe each piece of cake by giving the angles of the vanilla and strawberry parts, as in “
15
°
strawberry-
40
°
vanilla” or “
60
°
vanilla only.”
Suppose that Carlos and Angela are the dividers and Boris is the chooser. In the first division, Carlos cuts the cake vertically through the center as shown in Fig.3-24, with Angela choosing
s
1
(the left half) and Carlos
s
2
(the right half). In the second division, Angela subdivides
s
2
into three pieces.
a. Describe how Carlos would subdivide
s
2
into three pieces.
b. Describe how Angela would subdivide
s
1
into three pieces.
c. Based on the subdivisions in (a) and (b), describe a possible final fair division of the cake.
d. For the final fair division you described in (c), find the value (in dollars and cents) of each share in the eyes of the player receiving it.
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
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