Angeline and Brad are planning to divide the chocolate-strawberry cake shown in Fig 3-40(a) using the divider-chooser method, with Angelina being the divider. Suppose that Angelina values chocolate cake three times as much as she values strawberry cake. Fig 3-40(a) shows a generic cut made by Angelina dividing the cake into two shares s 1 and s 2 of equal value to her. Think of s 1 as an " x " chocolate- y ° strawberry” share. For each given measure of the angel x , find the corresponding measure of the angle of y . F i g u r e 3 - 3 0 F u l l A l t e r n a t i v e T e x t _ a. x = 60 ° . b. x = 72 ° . c. x = 108 ° . d. x = 120 ° .
Angeline and Brad are planning to divide the chocolate-strawberry cake shown in Fig 3-40(a) using the divider-chooser method, with Angelina being the divider. Suppose that Angelina values chocolate cake three times as much as she values strawberry cake. Fig 3-40(a) shows a generic cut made by Angelina dividing the cake into two shares s 1 and s 2 of equal value to her. Think of s 1 as an " x " chocolate- y ° strawberry” share. For each given measure of the angel x , find the corresponding measure of the angle of y . F i g u r e 3 - 3 0 F u l l A l t e r n a t i v e T e x t _ a. x = 60 ° . b. x = 72 ° . c. x = 108 ° . d. x = 120 ° .
Solution Summary: The author illustrates how Angeline and Brad are planning to divide the chocolate-strawberry cake using the divider-chooser method.
Angeline and Brad are planning to divide the chocolate-strawberry cake shown in Fig 3-40(a) using the divider-chooser method, with Angelina being the divider. Suppose that Angelina values chocolate cake three times as much as she values strawberry cake. Fig 3-40(a) shows a generic cut made by Angelina dividing the cake into two shares
s
1
and
s
2
of equal value to her. Think of
s
1
as an
"
x
"
chocolate-
y
°
strawberry” share. For each given measure of the angel
x
,
find the corresponding measure of the angle of
y
.
F
i
g
u
r
e
3
-
3
0
F
u
l
l
A
l
t
e
r
n
a
t
i
v
e
T
e
x
t
_
موضوع الدرس
Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
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